
Now, N = 100
⇒ \(\frac{N}2\) = 50.
The cumulative frequency just greater than 50 is 56 and the corresponding class is 150 - 155.
Thus, the median class is 150 – 155.
∴ l = 150, h = 5, f = 22, c f = c.f. of preceding class = 34 and \(\frac{N}2\) = 50.
Now,

= 150 + 3.64
= 153.64
Hence, the median = 153.64.