To find the mean let us put the data in the table given below:


= 49.7
Thus, mean of the given data is 49.7.
Now, to find the median let us put the data in the table given below:

Now, N = 100 ⇒ \(\frac{N}2\) = 50
The cumulative frequency just greater than 50 is 71 and the corresponding class is 45 – 55.
Thus, the median class is 45 – 55.
∴ l = 45, h = 10, N = 100, f = 33 and c f = 38.
Now,

= 45 + 3.64
= 48.64
Thus, the median is 48.64.
We know that,
Mode = 3(median) – 2(mean)
= 3 × 48.64 – 2 × 49.70
= 145.92 – 99.4
= 46.52
Hence, Mean = 49.70, Median = 48.64 and Mode = 46.52