Question

Find the roots of quadratic equation 2x² - x + 1/8 = 0

Answer 1

We write, - x = - x/2 - x/2 as 2x² \(\times\)1/8 = x²/4 = (- x/2) \(\times\) (- x/2)

∴ 2x² - x + 1/8 = 0

Hence, 1/4 is the repeated root of the given equation.