Use app×
QUIZARD
QUIZARD
JEE MAIN 2026 Crash Course
NEET 2026 Crash Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
4.1k views
in Geometric Progressions by (15.9k points)

Find an infinite G.P. whose first term is 1 and each term is the sum of all the terms which follow it.

Please log in or register to answer this question.

1 Answer

+1 vote
by (15.4k points)

As we have the first term of GP. Let r be the common ratio. 

∴ we can say that GP is 1 , r , r2 , r3 … ∞ 

As per the condition, each term is the sum of all terms which follow it. If a1,a2 , … represents first, second, third term etc 

∴ we can say that: a1 = a2 + a3 + a4 + …∞ 

⇒ 1 = r + r2 + r3 +…∞ 

Note: You can take any of the cases like a2 = a3 + a4 + .. all will give the same result.

We observe that the above progression possess a common ratio. So it is a geometric progression.

Common ratio = r and first term (a) = r

Sum of infinite GP = \(\frac{a}{1-k}\) ,where a is the first term and k is the common ratio. 

Note: We can only use the above formula if |k|<1 

∴ we can use the formula for the sum of infinite GP.

Hence the series is 1, 1/2, 1/4, 1/8, 1/16.........

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

...