Correct answer is (b) 2 cm
Given, AB = 5 cm, BC = 7 cm and CA = 6 cm.
Let, AR = AP = x cm.
BQ = BP = y cm
CR = CQ = z cm
(Since the length of tangents drawn from an external point arc equal)
Then, AB = 5 cm
\(\Rightarrow\) AP + PB = 5 cm
\(\Rightarrow\) x + y = 5 ......(i)
Similarly, y + z = 7 ....(ii)
and z + x = 6 .........(iii)
Adding (i), (ii) and (iii), we get:
(x + y) + (y + z) + (z + x) = 18
\(\Rightarrow\) 2(x + y + z) = 18
\(\Rightarrow\) (x + y + z) = 9 ........(iv)
Now, (iv) – (ii):
\(\Rightarrow\) x = 2
∴ The radius of the circle with center A is 2 cm.