Question

Draw a △ABC, right-angled at B such that AB = 3 cm and BC = 4cm. Now, Construct a triangle similar to △ABC, each whose sides is 7/5 times the corresponding side of △ABC.

Answer 1

Steps of Construction

Sept 1: Draw a line segment BC = 4cm

Sept 2: With B as center draw an angle of 90°

Step 3: With B as center and radius equal to 3cm cat an are at the night angle and name it A

Step 4: Join AB and AC

Thus, △ABC is obtained

Step 5: Extend BC to D, such that \(BD=\frac{7}{5}BC=\frac{7}{5}(4)cm=5.6cm\)

Step 6: Draw DE || CA cutting AB produced to E

Thus, △EBD is the required triangle, each of whose sides is \(\frac{7}{5}\)the corresponding sides of △ABC.