Question

A hemispherical bowl is made of steel, 0.25 cm thick. The inner radius of the bowl is 5 cm. Find the outer curved surface area of the bowl. [ Assume π = 22/7 ]

Answer 1

Inner radius of hemispherical bowl = 5 cm

Thickness of the bowl = 0.25 cm

∴ Outer radius (r) of hemispherical bowl = (5 + 0.25) cm

= 5.25 cm

Outer CSA of hemispherical bowl = 2πr²

= 2 x 22/7 x (5.25 cm)² = 173.25 cm²

Therefore, the outer curved surface area of the bowl is 173.25 cm².