Reduction in intensity after through first slab `= 20%`
Reduction in intensity after passing through second slab `= 20 %` of the intensity left (i.e., 80 %) after passing through first slab `= (1)/(5) xx 80% = 16 %`
Total reduction in intensity after passing through two consecutive slabs `= 20 % + 16 %`
=`36 %`.