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The matallic bob of a simple pendulum of mass 0.5 kg carries a positive charge of 0.25 C .If the pendu-lum is suspended in an electric fielf of strength `15 N C^(-1)` directed from east to west, state the forces acting on the bob and derive the condition for equilibrium. Also find the angle subtended at the equilibrium.
(Take `g = 10 ms^(-2)`)

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(i) On resolving the vectors `W = mg` and `F = qE`, we get `mg sin theta = qE cos theta (1)`
(at equilibrium position)
(ii) From (1)
`tan theta = (qE)/(mg)`
Substitute the values of `q,E,m` and g and obtain the angle subtended by the pendulum with the vertica.
(iii) `theta = tan^(-1) (0.75)`

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