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in Coordinate Geometry by (29.9k points)
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The perimeter of the triangle with vertices (0,4), (0,0) and (3,0) is

(a) (7 + √5)

(b) 5

(c) 10

(d) 12

1 Answer

+1 vote
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Best answer

Correct answer is (d) 12

Let A(0,4), B(0,0) and C(3,0) be the given vertices. So

Therefore

AB + BC + AC = 4 + 3 + 5 = 12.

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