Given: \(\frac{(1+i)(1+2i)}{(1+3i)}\)
To find: Multiplicative inverse
We know that,
Multiplicative Inverse of z = z-1
We solve the above equation
Now, we rationalize the above by multiplying and divide by the conjugate of (-1 + 3i)
Now, we know that,
(a + b)(a – b) = (a2 – b2)
So, eq. (i) become
Hence, Multiplicative inverse of
\(\frac{(1+i)(1+2i)}{(1+3i)}\) \(=\frac{4}{5}-\frac{3}{5}i\)