
= i + 1
Let Z = 1 + i = r(cosθ + i sinθ)
Now , separating real and complex part, we get
1 = rcosθ ……….eq.1
1 = rsinθ …………eq.2
Squaring and adding eq.1 and eq.2, we get
2 = r2
Since r is always a positive no., therefore,
r = √2,
Hence its modulus is √2.
Now, dividing eq.2 by eq.1 , we get,
\(\frac{rsin\theta}{rcos\theta}=\frac{1}{1}\)
Tanθ = 1
Since cosθ = 1/√2, sinθ = 1/√2 and tanθ = 1.
Therefore the θ lies in first quadrant.
Tanθ = 1, therefore θ = π/4
Representing the complex no. in its polar form will be
Z = √2{cos(π/4)+i sin(π/4)}