
Now, separating real and complex part, we get
1/√2 = rcosθ……….eq.1
1/√2 = rsinθ…………eq.2
Squaring and adding eq.1 and eq.2, we get
1 = r2
Since r is always a positive no., therefore,
r = 1,
Hence its modulus is 1.
Now , dividing eq.2 by eq.1 , we get,
\(\frac{rsin\theta}{rcos\theta}=\cfrac{\frac{i}{\sqrt2}}{\frac{i}{\sqrt2}}\)
tanθ = 1
Since cosθ = 1/2, sinθ, and tanθ =1.
Therefore the θ lies in first quadrant.
Tanθ = 1, therefore θ = π/4
Representing the complex no. in its polar form will be
Z = 1{cos(π/4)i sin(π/4)}