To find: the value of 9P0
Formula Used:
Total number of ways in which n objects can be arranged in r places (Such that no object is replaced) is given by,
nPr = \(\frac{n!}{(n-r)!}\)
Therefore,
9P0 = \(\frac{6!}{(6-6)!}\)
9P0 = 1
Thus, the value of 9P0 is 1.