To find: number of ways of arranging 5 subjects in 6 periods.
Condition: at least 1 period for each subject.
5 subjects in 6 periods can be arranged in P (6,5).
Remaining 1 period can be arranged in P (5,1)
Formula: Number of permutations of n distinct objects among r different places, where repetition is not allowed, is
P(n,r) = n!/(n-r)!
Total arrangements = P(6,5) × P(5,1) = \(\frac{6!}{(6-5)!}\times\frac{5!}{(5-1)!}\)
= \(\frac{6!}{1!}\times\frac{5!}{4!}\) = 720 × 5 = 3600.
Total number of ways is 3600 ways.
