Given: \(\lim\limits_{\text x \to \infty}\cfrac{(n+2)!+(n+1)!}{(n+2)!-(n-1)!} \)
We know that, (n + 2)! = (n + 2) × (n + 1)!
By putting the value of (n + 2)! , we get
Hence, \(\lim\limits_{\text x \to \infty}\cfrac{(n+2)!+(n+1)!}{(n+2)!-(n-1)!} \) = 1