For a number to be divisible by 5, the last digit should either be 5 or 0.
In this case, 5 is only possible.
For a four digit number to be between 3000 to 4000, in this case, should start with 3.
Therefore, the other 2 digits can be arranged by 4 numbers in P(4,2)
Formula:
Number of permutations of n distinct objects among r different places, where repetition is not allowed, is
P(n,r) = n!/(n-r)!
Therefore, a permutation of 4 different objects in 2 places is
P(4,2) = \(\frac{4!}{(4-2)!}\)
= \(\frac{4!}{2!}\) = \(\frac{24}{2}\) =12.
Therefore, there are 12 numbers present between 3000 to 4000 formed by using numbers 3,1,5,6,7,8.
