If the mirror were not present
` 1/f = 1/v - 1/u`
` 1/15 = 1/v - (-1/20)`
` 1/v = 1/15 - 1/20 `
` (20-15)/300 , v = 60` cm
The image would be formed at a distance of 50 cm from the mirror.
When the mirror is placed the image is formed as the position of the object.
That is the rays are reflected back along the same path.
This is possible only when the light rays are incident normally.
` :. 10 + R = 60` cm
R = 50 cm
f = 25 cm