Question

Each of the two guns, mounted on a rotating platform with their lengths parallel to each other, fires 20 bullets per second at a speed of 50 m `s^(-1)`. If the perpendicular distance between the two guns is 1.2 m and the mass of each bullet is 25g, find the couple acting on the platform.

Answer 1

(i) Force = Impulse `div`Time
(ii) Force on the gun = force on the bullets = m `((v-u)/(t))`, where v and u are final and initial velocities of bullets, respectively, and m = mass of each bullet.
(iii) Couple = force `xx` perpendicular distance between the forces.
(iv) 30 N m