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If 35Cn+7 = 35C4n–2 then find the value of n.

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Given: 35Cn+7 = 35C4n–2

Need to find: Value of n

We know,

One of the property of combination is: If nCr = nCt, then,

(i) r = t OR

(ii) r + t = n

Applying property

(i) we get,

⇒ n + 7 = 4n – 2

⇒ 3n = 9

⇒ n = 3

Applying property

(ii) we get,

⇒ n + 7 + 4n – 2 = 35

⇒ 5n = 30

⇒ n = 6

Therefore, the value of n is either 3 or 6.

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