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Prove that: 2cot45°cos15° = √3 + 1/2

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Prove that:

2cot45°cos15° = √3 + 1/2

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L.H.S

= 2cos45°cos15°

= 2cos45°cos(45° - 30°)

= \(\frac{\sqrt{3}\,+\,1}{\sqrt{2}}\)

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