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Find the mean, variance and standard deviation for the numbers 4, 6, 10, 12, 7, 8, 13, 12.

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Given data: 4, 6, 10, 12, 7, 8, 13, 12 

To find: MEAN 

We know that,

Mean (\(\overline{X}\)) = \(\frac{Sum\,of\,observations}{Total\,number\,of\,observations}\) 

\(\frac{4+6+10+12+7+8+13+12}{8}\) 

\(\frac{72}{8}\)

 \(\overline{X}\) = 9

To find: VARIANCE

To find: STANDARD DEVIATION

Standard Deviation (σ) = \(\sqrt{Variance}\)

\(\sqrt{9.25}\) 

= 3.04

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