Given data: 4, 6, 10, 12, 7, 8, 13, 12
To find: MEAN
We know that,
Mean (\(\overline{X}\)) = \(\frac{Sum\,of\,observations}{Total\,number\,of\,observations}\)
= \(\frac{4+6+10+12+7+8+13+12}{8}\)
= \(\frac{72}{8}\)
\(\overline{X}\) = 9
To find: VARIANCE


To find: STANDARD DEVIATION
Standard Deviation (σ) = \(\sqrt{Variance}\)
= \(\sqrt{9.25}\)
= 3.04