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Evaluate the following integrals:

\(\int \frac{(9x^2 - 4x + 5)}{(3x^3 - 2x^2 + 5x + 1)}dx\)

∫ (9x2 - 4x + 5)/(3x3 - 2x2 + 5x + 1) dx

1 Answer

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Best answer

Let 3x3 - 2x2 + 5x + 1 = t

⇒ (9x2 - 4x + 5)dx = dt

Putting this value in equation (i)

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