Question

4g equimolar mixture of NaOH and Na₂CO₃ contains x g of NaOH and y g of Na₂CO₃. The value of x is ....g. (Nearest integer)

Answer 1

Answer is: 1

Total mass = 4g 

Now 

NaOH : a mol  W_{NaOH +} W_Na2CO3 = 4

NaOH : 'a' mol ⇒ 40a + 106 a = 4

⇒ 40a + 106a = 4

⇒a = \(\frac{4}{146}\) mol

⇒ therefore mass of NaOH is : \(\frac{4}{146}\times 40g\) 

= 1.095 = 1