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+1 vote
26.5k views
in Physics by (45.1k points)

Two identical tennis balls each having mass 'm' and charge 'q' are suspended from a fixed point by threads of length 'l'. What is the equilibrium separation when each thread makes a small angle 'θ' with the vertical ?

(1) \(x = \left(\frac{q^2l}{2\pi\varepsilon_0 mg}\right)^{\frac{1}{2}}\)

(2) \(x = \left(\frac{q^2l}{2\pi\varepsilon_0 mg}\right)^{\frac{1}{3}}\)

(3) \(x = \left(\frac{q^2l^2}{2\pi\varepsilon_0 m^2g}\right)^{\frac{1}{3}}\)

(4) \(x = \left(\frac{q^2l^2}{2\pi\varepsilon_0 m^2g^2}\right)^{\frac{1}{3}}\)

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1 Answer

+2 votes
by (47.5k points)

Correct answer is 2.

by (15 points)
Thanks Bro/Sis

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