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+3 votes
15.0k views
in Physics by (38.4k points)

A boy reaches the airport and finds that the escalator is not working. He walks up the stationary escalator in time t1. If he remains stationary on a moving escalator then the escalator takes him up in time t2. The time taken by him to walk up on the moving escalator will be:

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1 Answer

+4 votes
by (40.3k points)

Correct option is (3) \(\cfrac{t_1t_2}{t_2+t_1}\)
L = Length of escalator

Vb/esc = \(\cfrac{L}{t_1}\)

When only escalator is moving.

Vesc = \(\cfrac{L}{t_2}\) 

when both are moving

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