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+2 votes
6.7k views
in Physics by (38.4k points)

A series LCR circuit of R = 5Ω, L = 20 mH and C = 0.5 µF is connected across an AC supply of 250 V, having variable frequency. The power dissipated at resonance condition is_____× 102 W.

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1 Answer

+1 vote
by (40.3k points)

Answer is 125

XL = XC (due to resonance)
Z = R so irms = \(\cfrac{V}{Z}=\cfrac{V}{R}\)

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