The equilibrium constant for the reaction ​ A(s) ⇌ M(s) 1/2 O2(g) ​

Question

The equilibrium constant for the reaction 

A(s) ⇌ M(s) \(\frac{1}{2}\)O₂(g)

is Kp = 4. At equilibrium, the partial pressure of O₂ is ....... atm. (Round off to the nearest integer)

Answer 1

Answer is :16

k_p = PO^1/2 = 4

PO₂ = 16 bar = 16 atm