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If `tan(A+B)=sqrt(3)`and `t a n(A- B)=1/(sqrt(3));``0^@ le A + B le 90^@` and ` A le B ,`find A and B.

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If `tan(A+B)=sqrt(3)`and `t a n(A- B)=1/(sqrt(3));``0^@ le A + B le 90^@` and ` A le B ,`find A and B.
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Here, `tan(A+B) = sqrt3 = tan60^@`
So, `A+B=60^@->(1)`
`tan(A-B) = 1/sqrt3 = tan30^@`
So, `A-B=30^@->(2)`
Adding (1) and (2),
`2A = 90 => A = 45^@`
Putting value of A in (1),
`B = 60 -45 = 15^@`
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