Question

If Zeba were younger by 5 years than what she really is, then the square of her age (in years) would have been 1 more than five times her actual age. What is her age now?

Answer 1

Let the present age of Zeba=x years
5 years ago, her age =(x-5) years
According to given condition
`(x-5)^(2)=5x+11`
`(x-5)^(2)=5x+11`
`impliesx^(2)-(14+1)x+14=0impliesx^(2)-14x-x+14=0`
`impliesx(x-14)-1(x-14)=0implies(x-14)(x-1)=0`
`impliesx-14=0orx-1=0`
`impliesx=14orx=1`
But x=1 is impossible because then x-5=-4
`because` Present age of Zeba =14 years