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In Fig. 6.2, ∠BAC = 90° and AD ⊥ BC. Then,

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In Fig. 6.2, ∠BAC = 90° and AD ⊥ BC. Then,

(A) BD . CD = BC2 (B) AB . AC = BC2

(C) BD . CD = AD2 (D) AB . AC = AD2

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Correct answer is (C) BD . CD = AD2 

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