Answer :
1. Answer : (c) double dumb bell
Explanation: The ml values for five d orbitals are -2, -1, 0, +1, and +2 i.e., we can say d-subshell has five orientations. All these d-orbitals have the same energy and are called degenerate orbitals. Hence, we can say d-orbitals have double dumbbell-shaped.
2. Answer : (a) ns2
Explanation: The general electronic configuration of alkaline earth elements is ns2. These elements have two valence electrons in the outermost s shell.
3. Answer : (b) effective nuclear charge
Explanation: Lanthanoid contraction effect results from poor shielding of nuclear charge (nuclear attractive force on electrons) by 4f electrons so effective nuclear charge increases; the 6s electrons are drawn towards the nucleus, thus resulting in a smaller atomic radius.
4. Answer : (d) Zn2+
Explanation: Zn2+ = [Ne 3s2 3p6 4s0 3d10] It is diamagnetic, so no unpaired e−s.
5. Answer : (d) d-d transition
Explanation: Colour of transition metal ions are due to absorption of the same wavelength. This results in d−d transition.
6. Answer : (b) Cu >Au > Ag
Explanation: Hence the melting point decreases from copper to silver, but the melting point of gold becomes even higher than silver due to its higher density that happened due to contraction.
7. Answer : (a) Ti+, Ti3+
Explanation: Ti+ ions are more stable than Ti3+ and thus, Ti3+ ions change to Ti+ ions thereby acting as oxidising agents.
8. Answer : (b) lanthanoid contraction
Explanation: Zr and Hf have almost similar atomic and ionic radii it can be explained on the basis of shielding effect . Due to lanthanide contraction. Moreover, the electrons which are present in inner shells, shields outer electrons from nuclear charge, after that they experience a low effective nuclear charge.
9. Answer : (d) Copper
Explanation: Malachite, a minor ore but a widespread mineral of copper, basic copper carbonate, Cu2CO3(OH)2. Because of its distinctive bright green colour and its presence in the weathered zone of nearly all copper deposits, malachite serves as a prospecting guide for that metal.
10. Answer : (d) Cinnabar
Explanation: Cinnabar is an ore of mercury.
11. Answer : (c) Manganese
Explanation: Manganese has the highest oxidation state because the number of unpaired electrons in the outermost shell is more, i.e. 3d5 4s2.
12. Answer : (b) Cu + Sn + Zn
Explanation: Gunmetal, also called G Metal, variety of bronze, formerly used for ordnance. Modern admiralty gunmetal is composed of 88 percent copper, 10 percent tin, and 2 percent zinc and is used for gears and bearings that are to be subjected to heavy loads and low speeds.
13. Answer : (c) Cu, Zn, Ni
Explanation: German Silver is an alloy of copper, zinc and nickel, sometimes also containing lead and tin.
14. Answer : (d) Al 95%, Cu 4%, Mn 0.5%, Mg 0.5%
Explanation: Duralumin is an alloy 95% aluminium, 4% copper, 0.5% manganese and 0.5% magnesium.
15. Answer : (b) Cassiterite
Explanation: Cassiterite was the main tin ore throughout ancient history and remains the most important source of tin today. Thus we can say that cassiterite isn't an ore of iron.
16. Answer : (d) Eu
Explanation: Lanthanides show variable oxidation states. The most stable oxidation state of Lanthanides is +3. They also show +2 and +4 oxidation states due to the presence of either half filled or completely filled or empty 4f sub shell. Due to stable half filled configuration Eu shows +2 configuration.
17. Answer : (a) SbF5
Explanation: F2 is the formed by reacting K2MnF6 with Sb5. Reaction is as follows:
K2MnF6 + 2SbF5 → 2KSbF6 + MnF3 + \(\frac{1}{2}\)F2
18. Answer : (d) Co -60
Explanation: Co-60 is used as anti-cancerous among the given radioactive isotopes. It emits \(\beta\)− particles and energetic gamma rays, for which reason it is used in radiation therapy.
19. Answer : (b) Black
Explanation: When hydrogen sulphide gas is passed through a blue solution of copper sulphate, a black precipitate of copper sulphide is obtained and the sulphuric acid so formed remains in the solution.
20. Answer : (a) Diamagnetic
Explanation: Transition elements have one or more unpaired electrons. Due to the presence of these unpaired electrons, they show paramagnetism. Thus, transition metals are not diamagnetic. They are good conductors of heat and electricity. They form complexes and show variable oxidation state as d orbitals are gradually filled up in the transition series.
21. Answer : (a) (n-1) d
Explanation: In these elements, the last electron enters the d orbital of the penultimate shell i.e. the last electron goes to (n-1) d orbital. Hence these elements are named as d-block elements.
22. Answer : (d) transition elements
Explanation: Elements which exhibit both vertical and horizontal similarities are transition elements. They show vertical similarity because of same electronic configuration. They show horizontal similarity because of similar size.
23. Answer : (a) Fifth
Explanation: The outermost shell and one shell prior to it in d subshell, has total 5 electron so it will be placed in fifth group in transition element or 'd' block of periodic table.
24. Answer : (b) 2
Explanation: Nickel has two unpaired electrons in the 3d sublevel. When nickel ionizes to the +2 state it loses the two electrons in the 4s, so there are still two unpaired electrons in Ni2+.
25. Answer : (b) fluorides
Explanation: The highest oxidation states of transition metals are shown by fluorides and oxides as fluorine and oxygen are the most electronegative elements. The highest oxidation state shown by any transition metal is +8.
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