Question

Two balls of masses M₁ and M₂ are placed on a horizontal frictionless table connected by a spring as shown in figure, now mass M₂ is pulled to the right with a force F. If the acceleration of mass M₁ is a, then acceleration of mass M₂ will be

(a) \(\frac{F}{M_1}\)

(b) \(\frac{ F - M_1a}{M_2}\)

(c) \(\frac{F}{M_2}\)

(d) None of these

Answer 1

Correct option:  (b) \(\frac{ F - M_1a}{M_2}\)

Force acting on mass M₁ is f = M₁ a. Mass M₁ will pull mass M₂ towards left with a force f.

Net force acting on mass M₂ = F - f

= F - M₁a

Acceleration of mass M₂ \(=\frac{F - M_1a}{M_2}\)