
∫ ((log x)/(1 + log x)2) dx
⇒ log x = A (1 + log x) + B
For x = 1, equation: 0 = A + B
For x = 1/e, equation: -1 = B i.e. B = -1
So, A = 1

Tip – If f1(x) and f2(x) are two functions , then an integral of the form ∫ f1(x)f2(x)dx can be INTEGRATED BY PARTS as

where f1(x) and f2(x) are the first and second functions respectively.
Taking f1(x) = 1/(1 + log x) and f2(x) = 1in the second integral and keeping the first integral intact,

where c is the integrating constant.