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sin (45° + θ) – cos (45° – θ) is equal to (A) 2cosθ (B) 0 (C) 2sinθ (D) 1

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sin (45° + θ) – cos (45° – θ) is equal to

(A) 2cosθ (B) 0 (C) 2sinθ (D) 1
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Correct answer is (B) 0 

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