∫ √(6x+4)dx = ?, x ∈[0,2], A. 64/9 B. 7 C. 56/9 D. 60/9

Question

Mark against the correct answer in the following:

\(\int\limits_0^2\sqrt{6x+4}dx=?\)

∫ √(6x+4)dx = ?, x ∈[0,2]

A. \(\cfrac{64}{9}\)

B. 7 

C. \(\cfrac{56}{9}\) 

D. \(\cfrac{60}{9}\)

Answer 1

Correct answer is : C.\(\cfrac{56}{9}\)