Use app×
QUIZARD
QUIZARD
JEE MAIN 2026 Crash Course
NEET 2026 Crash Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
263 views
in Physics by (49.4k points)
closed by

The molecules in a perfect gas has mean kinetic energy (at 27°C) of 7 x 10-4 erg and acceleration due to gravity 980 cm s−2. Then, the number of molecules in 2 cc of this gas at 27° C at a pressure of 10 cm of Hg is

(a) 4.28 x 107

(b) 3.52 x 108

(c) 4.75 x 108

(d) 5.71 x 108

1 Answer

+1 vote
by (51.0k points)
selected by
 
Best answer

Answer is : (d) 5.71 x 108

KE of the given gas at 27° C

∴ Number of molecules in the given volume = KE of given gas/KE of a molecule of gas

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

...