Answer is : (b) 1
It is given that for prime numbers p1, p2, p3, p4 the special prime number
p = p1 + p2 = p3 - p4
Case I
If all p1, p2, p3, p4 are odd, then (p1 + p2 ) and (p3 - p4) are even, which is not possible.
Case II
If one of p1 and p2 is even, say p2 is 2 and p4 must be 2.
So, p = p1 + 2 = p3 - 2
the above equation is satisfied only if
p = 5, p1 = 3 and p3 = 7
So, the number of special prime p is 1.