Question

Find the magnitude and direction of current in 1Ω resistor in the given circuit.

Answer 1

For the mesh APQBA

– 6 – 1(I₂ – I₁) + 3I₁ = 0

Or – I₂ + 4I₁ = 6 ...(1)

For the mesh PCDQP

2I₂ – 9 + 3I₂ + 1 (I₂ – I₁) = 0

Or 6I₂ – I₁ = 9 ...(2)

Solving (1) and (2), we get

I₁ = \(\frac{45}{23}A\) and I₂ = \(\frac{42}{23}A\)

∴ Current through the 1 Ω resistor = (I₂ - I₁) = \(\frac{-3}{23}A\)