Question

The lower stability of ethyl anion compared to methyl anion and the higher stability of ethyl radical compared to methyl radical, respectively, are due to

(a) + I-effect of the methyl group in ethyl anion σ → p-orbital conjugation in ethyl radical

(b) − I-effect of the methyl group in ethyl anion and σ → σ * conjugation in ethyl radical

(c) + I effect of the methyl group in both cases

(d) + I- effect of the methyl group in ethyl anion and σ → σ * conjugation in ethyl radical

Answer 1

Answer is : (a) + I-effect of the methyl group in ethyl anion σ → p-orbital conjugation in ethyl radical

The lower stability of ethyl anion (CH₃ CH₂) compared to methyl anion (CH₃^-) is because of + I-effect of methyl group of ethyl anion. The higher stability of ethyl radical compared to methyl radical is due to σ − p-orbital conjugation which is known as hyper conjugation in ethyl radical.