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For the network junction shown below, find out the current I3, given that I1 = 3 A, I2 = 4 A and I4 = 2 A.

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According to KCL, incoming currents= outgoing currents

I1 + I3 = I2 + I4

Or, I3 = -I1 + I2 + I4 = -3 + 4 + 2 = 3 A.

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