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Calculate the equivalent capacitance between points A and B in the circuit below. If a battery of 10 V is connected across A and B, calculate the charge drawn from the battery by the circuit.

\(\therefore\quad\cfrac{C_1}{C_2}=\cfrac{C_3}{C_4}\)

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This is the condition of balance so there will be no current across PR (50 µF capacitor)

Now C1 and C2 are in series

Equivalent capacitance between A and B is

Hence, charge drawn from battery (Q) = CV

= 10 × 10 µC = 100 µC = 10–4 C

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