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In the reaction, x and y, respectively are (a) x = CH3OH; y = Pd / BaSO4, quinoline, H2 (b) x = CH3I; y = Pd / BaSO4, quinoline, H2

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In the reaction,

x and y, respectively are

(a) x = CH3OH; y = Pd / BaSO4, quinoline, H2

(b) x = CH3I; y = Pd / BaSO4, quinoline, H2

(c) x = CH3I; y = Na in liq. NH3

(d) x = CH3OH; y = Na in liq. NH3

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Answer is : (c) x = CH3I; y = Na in liq. NH3

Thus, in the given reaction,

x = CH3I and y = Na / liq. NH3

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