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0 votes
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in Laws of motion by (15.3k points)
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The kinetic energy k of a particle moving along a circle of radius R depends on the distance covered s as k= as2  where a is a constant. The total force acting on the particle is:

(A) \(2a\frac{s^2}{R}\)

(B) 2as \(\left(\frac{s^2}{R^2}\right)^{1/2}\)

(C) 2as

(D) 2as \(\frac{R^2}{s^2}\)

2 Answers

+1 vote
by (39.0k points)
selected by
 
Best answer

Correct option is (B) \(2as \left(\frac{s^2}{R^2}\right)^{1/2}\)

Kinetic energy k = 1/2 mv2

But given that k = as2

+1 vote
by (15.9k points)

Correct answer is (B) 2as \(\left(\frac{s^2}{R^2}\right)^{1/2}\)

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