Answer is : (a) cos-1(1/3)
Let length of each of rod is l and angle between them is θ.

Let the lower rod is horizontal and upper rod makes θ angle with horizontal. Weights of rods acts vertically downwards from their centres A and B as shown in above figure.
Now, perpendicular distance of weight acting through point A from point D is

and perpendicular distance of weight acting through B from point D is

At equilibrium torque of these two weights about D must balance each other,
