Question

The ratio of angular speed of second hand to that of the minute hand of a clock is 

(A) 60 : 1 

(B) 1 : 60 

(C) 1 : 1 

(D) 1 : 6

Answer 1

Answer is (A) 60 : 1

Period of second hand = T_s = 60 s and

Period of minute hand = T_m = 60 x 60 = 3600 s

Angular speed of second ω_s = \(\frac{2\pi}{T_s}\) = \(\frac{2\pi}{60}\)

Angular speed of second ω_s  = \(\frac{2\pi}{T_m}\) =   \(\frac{2\pi}{3600}\)