Question

A mass of 5 kg is tied to a string of length 1.0 m and is rotated in vertical circle with a uniform speed of 4 m/s. The tension in the string will be 130 N when the mass is at (g = 10 m/s²)

(A) highest point 

(B) mid way 

(C) bottom 

(D) cannot be justified

Answer 1

Answer is (C) bottom

Using,

T_L = \(\frac{mv^2L}{r}\) + mg = 6 mg = 6 x 5 x 10 = 130 N

∴ The mass is at the bottom position