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For any base show that log (1 + 2 + 3) = log 1 + log 2 + log 3.

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For any base show that

log (1 + 2 + 3) = log 1 + log 2 + log 3.

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1 Answer

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L.H.S. = log (1 + 2 + 3)

= log 6 = log (1 \(\times\) 2 \(\times\) 3) 

= log 1 + log 2 + log 3 

= R.H.S.

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