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In a circle of diameter 66 cm, the length of a chord is 33 cm. The length of minor arc of the chord is 

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In a circle of diameter 66 cm, the length of a chord is 33 cm. The length of minor arc of the chord is 

(A) 33π cm 

(B) 11π cm 

(C) 22π cm 

(D) 5.5π cm

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(B) 11π cm 

Let ‘O’ be the centre of the circle 

d = 66 cm 

⇒ r = 33 cm 

∆OAB is an equilateral triangle

⇒ \(\theta\) = 60° = πc/3

l(minor arc AB) = r\(\theta\) 

= 33 x π/3 

= 11π cm

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