Question

Let [ɛ₀] denote the dimensional formula of the permittivity of vacuum. If M = mass, L = length, T = time and A = electric current, then

(A) [ɛ₀] = [M^–1 L^–3 T² A] 

(B) [ɛ₀] = [M^–1 L^–3 T⁴ A²] 

(C) [ɛ₀] = [M^–1 L² T^–1 A^–2] 

(D) [ɛ₀] = [M^–1 L² T^–1 A]

Answer 1

Answer is (B) [ɛ₀] = [M^–1 L^–3 T⁴ A²]